Run Details #623
Model
OLMo 3 7B (LMStudio)
Score
0
Correct (≥100)
0/1
Incorrect (<100)
1
Median Time
5780.0ms
Tokens Used
348
Cost
289µ$
Benchmark:
0303_python_letter_count
Run Date: 2026-03-02 20:30:58
Coding question results (1)
0303_python_letter_count:0
Incorrect
Score: 0 • 5780ms • 348 tokens • 289µ$
Question: Write Python 3.12 code only.
Define exactly one function named count_target_letter(text, target).
Return how many times the target letter appears in the string.
Count should be case-insensitive.
Raise TypeError for non-string input, and raise ValueError if target is not exactly one character.
Do not use any imports (no numpy, requests, or other libraries).
Sandbox note: dunder attribute access is blocked (for example, type(x).__name__). Avoid names/attributes starting with '__'.
Expected output format:
- Return exactly one fenced Markdown code block starting with ```python and ending with ```.
- Put only valid Python code inside that block (no prose before/after).
- Use 4 spaces for indentation (not tabs).
- Do not return JSON and do not wrap code in a "function" key.
Sample input/output behavior:
- count_target_letter("Mississippi", "s") -> 4
Task:
Write a Python 3.12 function for 'how many times does the target letter appear in a string'.
Submitted code
def count_target_letter(text, target):
if not isinstance(text, str):
raise TypeError("text must be a string")
if not isinstance(target, str) or len(target) != 1:
raise ValueError("target must be exactly one character")
lower_text = text.lower()
lower_target = target.lower()
cnt = 0
for ch in lower_text:
if ch == lower_target:
cnt += 1
return cnt
```
Test case results
| # | Status | Args | Expected | Actual | Error |
|---|---|---|---|---|---|
| 0 | Fail | - |
- |
- |
SyntaxError: invalid syntax |