Run Details #637

Question: Write Python 3.12 code only. Define exactly one function named min_coins_for_amount(amount, coins). Return the minimum number of coins needed to make the amount exactly. If exact change is impossible, raise ValueError. Raise TypeError for invalid input types. Do not use any imports (no numpy, requests, or other libraries). Sandbox note: dunder attribute access is blocked (for example, type(x).__name__). Avoid names/attributes starting with '__'. Expected output format: - Return exactly one fenced Markdown code block starting with ```python and ending with ```. - Put only valid Python code inside that block (no prose before/after). - Use 4 spaces for indentation (not tabs). - Do not return JSON and do not wrap code in a "function" key. Sample input/output behavior: - min_coins_for_amount(44, [1, 4, 22]) -> 2 Task: Write a Python 3.12 function for making change with the fewest coins (e.g., 78c with 1c, 4c, 22c).

Submitted code

def min_coins_for_amount(amount: int, coins: list[int]) -> int:
    """
    Calculate the minimum number of coins needed to make a certain amount.
    
    Args:
    - amount (int): The target amount in cents.
    - coins (list[int]): A list of available coin denominations in cents.
    
    Returns:
    - int: The minimum number of coins needed.
    
    Raises:
    - ValueError: If exact change is impossible.
    - TypeError: For invalid input types.
    """
    
    # Check for valid input types
    if not isinstance(amount, int) or not all(isinstance(coins, int) for coins in coins):
        raise TypeError("Amount must be an integer and coins must be a list of integers.")
        
    # Initialize dynamic programming table with infinite values
    dp = [float('inf')] * (amount + 1)
    
    # Base case: 0 coins needed to make amount 0
    dp[0] = 0
    
    # Calculate minimum number of coins for each amount up to the target
    for i in range(1, amount + 1):
        for coin in coins:
            if i >= coin and dp[i - coin] != float('inf'):
                dp[i] = min(dp[i], dp[i - coin] + 1)
                
    # Raise ValueError if exact change is impossible
    if dp[amount] == float('inf'):
        raise ValueError("Exact change is impossible.")
        
    return dp[amount]