Run Details #821

Question: Write Python 3.12 code only. Define exactly one function named count_target_letter(text, target). Return how many times the target letter appears in the string. Count should be case-insensitive. Raise TypeError for non-string input, and raise ValueError if target is not exactly one character. Do not use any imports (no numpy, requests, or other libraries). Sandbox note: dunder attribute access is blocked (for example, type(x).__name__). Avoid names/attributes starting with '__'. Expected output format: - Return exactly one fenced Markdown code block starting with ```python and ending with ```. - Put only valid Python code inside that block (no prose before/after). - Use 4 spaces for indentation (not tabs). - Do not return JSON and do not wrap code in a "function" key. Sample input/output behavior: - count_target_letter("Mississippi", "s") -> 4 Task: Write a Python 3.12 function for 'how many times does the target letter appear in a string'.

Submitted code

def count_target_letter(text, target):
    """Return how many times the target letter appears in the string."""

    # Check input type and raise TypeError if not string
    if not isinstance(text, str) or not isinstance(target, str):
        raise TypeError("Inputs must be strings.")

    # Check target length and raise ValueError if non-single character
    if len(target) != 1:
        raise ValueError("Target letter must be single character.")

    # Initialize count to zero
    count = 0

    # Iterate through characters in the string, ignoring non-letter characters
    for char in text:
        # Ignore special case for 's' (if not 'S')
        if char.lower() == target.lower():
            # Increment count when matching letter
            count += 1

    return count


# Test with sample inputs and expected outputs
print(count_target_letter("Mississippi", "s"))  # Expected output: 4